Home
Equations with Parentheses
Homework 6 Integration
math final exam
Radial basis functions for simulating PDEs
Mahtematics Courses
Inverse Functions
Polynomial Division;The Remainder and Factor Theorems
MATH 120 Exam 1 Information
Evaluating Variable Expressions
Basic Mathematics Skills
Lexical templates at the base of the layered architecture of the LCM
Developmental Mathematics Course Information
Facts to Remember
Quadratic Function
Assessment Sample Question for M
Math 100 Study Guide for the Fin
Math Standards
INTERMEDIATE ALGEBRA
Factoring Polynomials
Precalculus I
Greek Numbers and Arithmetic
Precalculus Course Outline
beginalgebra_contents
Math 2700 Key Concepts
MATH 215 Linear Algebra
Elementary Linear Algebra Autumn 2008
Singular Values
Linear Equations in Two Variables
A catalog of essential functions
Partial Fractions,Long Division
MATH 128-003 Exam
Math 150 Final Exam Review
College Algebra
Polynomial equations and solving them
MTH 098
Information and Entropy
Intermediate Algebra EXPONENTS
Linear Equations and Inequalities
Linear Equations in Two Variables
GRAPHING LINEAR EQUATIONS IN TWO VARIABLES
Literal Equations Practice
ITERATIVE METHODS FOR SOLVING LINEAR EQUATIONS
Foundations of Advanced Mathematics
Intermediate Algebra
Calculus I:Sample Exam 4
FACTORING EXPRESSIONS INVOLVING RATIONAL EXPONENTS
Properties of Logarithms
Math 1051 Pre-calculus I Lecture Notes
Intermediate Algebra
HOMEWORK 05 SELECTED SOLUTIONS
Mathematics Problem Solving
MATH 10 - COLLEGE MATHEMATICS
MATH OBJECTIVES
NUMBER - RATIONAL NUMBERS
Literal Functions and Formulas
MATH 104 Beginning Algebra
Intermediate Algebra
Factoring Expressions
Introduction to rational functio
The Language of Mathematics Functions
Sample Test Problems for Mathematics
MATH 097 Developmental Math
Solving Equations & Inequalities
Review of Chapter 1
Inverse Functions Facts
Matrix Operations on a Casio Graphing Calculator
Adding & Subtracting Fractions
Engineering-Calculus-1
Math 444 Homework 4
Exponential Functions
ALGEBRA SUGGESTED HOMEWORK AND COURSE OBJECTIVES
Mathematics
Applications of Matrices and Linear Algebra
Math Courses
GEOMETRY DEFINITIONS
Differential and Integral Calculus Review and Tutorial
Linear Equations
Polynomial Functions
LINEAR ALGEBRA
INTERMEDIATE ALGEBRA
Adding and Multiplying Fractions
MTH 125 - Finite Mathematics
Intermediate Algebra
Algebra A Class
Math 130 Midterm Examination
INTERMEDIATE ALGEBRA
Subtracting Mixed Numbers
Simplification, Multiplication and Division of Rational Expressions
MATH 120 PREREQUISITE SKILLS
Functions II
INTERMEDIATE ALGEBRA
Calculus 1
Perimeter, Area, and Volume
MATH 701 Quadratics Solutions
Math 131 Test questions
The St. Louis Gateway Arch
Algebra II A
Addition and Subtraction of Rational Numbers
Linear Equations and Formulas

HOMEWORK 05 SELECTED SOLUTIONS

Exercise 5.2. You have a party tonight, so you decide to buy beer and pork
(for BBQ) in a grocery store. According to the price tag, you have to pay b
dollars for beer and p dollars for pork. Assume that beer is taxable (Texas
state tax is 8.25%, it is equivalent to the factor 0.0825), and beef is tax free.

a) Which algebraic expression represents the tax you pay?
b) Which algebraic expression represents the price of your purchase before tax?
c) What is the total price of your purchase?
d) Assume that b = 20 and p = 15. Plug these values into a), b), and c).

Solutions. You pay b+p dollars for beer and pork before tax and 0.0825 · b
dollars as state sale tax. The total price is 1.0825 · b + p dollars.

If b = 20 and p = 15 then the price before tax is 35 dollars, the tax is
0.0825 · 20 = 1.65 dollars. The total amount is 36.65 dollars.

Exercise 5.3. Determine whether the value(s) is(are) a solution to the equation.

a). Plugging x = −3 we get 16 = 40, which is, of course, false. Thus, x = −3
is not a solution of the above equation.

b). Plugging the numbers, we get 169 = 169, which is true. Thus, this triple
is a solution.

Exercise 5.4. Simplify the algebraic expression by combining like terms.

= combine like terms
  simplifying

Exercise 5.5. Solve the linear equation

Solution. a)

open parenthesis
simplifying
moving t to the LHS
 
adding 4 to both sides
 

Exercise 5.6. A 20 lb bag of grass seed will cover an area of 10000 ft2.

• How many pounds are needed to cover an area of 140000 ft2?
• How many bags of grass seed must be purchased to cover an area of 140000 ft2?

Solution. Let x be the weight of grass seeds (in pounds) needed to cover 140000 ft2. Then, we get the relation

area which can be covered with 1 lb

which is equivalent to

10000 · x = 140000 · 20

from which we conclude

The number of bags is

Exercise 5.9. (Temperature conversion). The temperature K (absolute/Kelvin
scale) and the temperature F (Fahrenheit scale) are related with the formula

• Use google/wikipedia website to find out what does 0 degrees K rep-
resent. Are there negative temperatures in K? Are there negative
temperatures in F?
• Find F when K = 0 (absolute zero);
• Find K when F = 100;

Solution. Kelvin scale is an absolute scale and 0 K is the lowest possible
temperature in our world. Therefore, if you see negative Kelvin temperature,
then there is a mistake. In Fahrenheit scale, negative scales are possible.

Plugging K = 0 into the equation we get

Thus, there are no temperatures less than −459.67 degrees on the Fahrenheit scale.

Plugging F = 100 we get

Exercise 5.10. (Weight gain/loss). A person’s body mass index (BMI) is
found by formula

where w is the person’s weight (in pounds), and h is the person’s height (in
inches). Lance Bass is 6 ft tall and weighs 200 lb.

a) Read wikipedia about BMI. Indicate when person is underweight, over-
weight, or have an optimal weight.
b) Determine Lance’s BMI.
c) Use wikipedia chart to see in which category the Lance’s weight is.
d) If Lance would like to have BMI of 20, how much weight would he need to gain/lose?
e*) Find/estimate your weight and your height, compute your BMI. Which
is your weight category? * Remark. Answer this part on a separate
sheet of paper, DO NOT turn it in.

Solution. According to the wikipedia chart, we have optimal weight if 18.5 ≤
BMI≤25. You are underweight if your body mass index is less than 18.5,
and you are overweight if this index is greater than 25.

Lance is 6 · 12 = 72 inches tall. Thus, his index is

Thus, Lance is overweight.

Assume that Lance wants to have BMI = 20 then he must have the weight
w20 satisfying

which is equivalent to w20 = 20 · 722 ÷ 703 = 147.48. Therefore, Lance has
to loose 200 − 147.48 = 52.52 pounds :) . I guess Lance is an optimist.

Exercise 5.11.

a) Solve the equation 9x + 4z = 7 + 8y for y.
b) Solve the equation 9x + 4z = 7 + 8y for z.
c) Solve the equation S = πr^2 + πrs for s.
d) Solve the equation A = 1/2h(b1 + b2) for b2.

Solution. Consider, for instance, parts c) and d).

Exercise 5.13. Set up an equation that can be used to solve the problem.
Solve the equation and find the desired value.

a) Miguel Garcia purchases two pairs of pants at the Gap for $60. If one
pair was $10 more than the other, how much was the more expensive pair?

b) The Gilberts purchased a car. If the total cost, including 5% tax sales
tax, was $14,512, find the cost of the car before tax.

Solution. a). Let x denote the cost of the more expensive pair. Then, the
price of the other pair is x − 10 dollars. Then, we get the equation

Thus, the more expensive pair costs 35 dollars. Less expensive pair is 35 − 10 = 25 dollars.

Solution. b). Let x denote the cost of the car before tax. Then, the sales
tax is 0.05x and the total cost of the car is x + 0.05x = 1.05x dollars. Thus,
we get the equation

1.05x = 14512

from which we get

dollars.